deliver us the moon electric cables rotation engine

Its value being R g, denoted radius of gyration, the effective velocity of the mass at n revolutions per second will be V n = 2 π R g n and its kinetic energy E = ½ M V n 2 = ½ M (2 π R g n) 2. 1, the method consists in selecting judiciously a number of points as o 1, o 2, o 3, etc., within the straight rod or mass M, respectively at distances r 1, r 2, r 3, etc., from the axis of rotation O and calculating the square root of the mean square of these distances. 1, 2, 3 and 4 and may be found more or less suitable. The kinetic energy of a rotating mass can be determined in four ways which are illustrated in diagrams, Figs. I trust that the following amplified statement will meet all of the objections raised and convert to my views those who are still unconvinced. Meanwhile many letters have reached me in which certain phenomena presented by rotating bodies, as the moon’s librations of longitude, are cited as evidences of energy due to spinning motion, i.e., proofs of axial rotation of the satellite in the true physical sense. Due to the printer’s error these were lost and, in consequence, I found it necessary to forward another communication which, unfortunately, was received too late for embodiment in the May number. In revising my article on “ The Moon’s Rotation”, which appeared in the April issue of the Electrical Experimenter, I appended a few remarks to the original text in further support and elucidation of the theory advanced. Knowing These Values and the Speed of Rotation the Kinetic Energy of the Mass is Readily Computed This Figure Shows the Selection of a Number of Points Taken WithIn the Straight Rod or Mass M, at Successive Distances from the Axis of Rotation O. In Determining the Kinetic Energy of a Rotating Mass.

Deliver us the moon electric cables rotation engine